3x(4x+1)(x^2-7)=0

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Solution for 3x(4x+1)(x^2-7)=0 equation: 


Simplifying
3x(4x + 1)(x2 + -7) = 0

Reorder the terms:
3x(1 + 4x)(x2 + -7) = 0

Reorder the terms:
3x(1 + 4x)(-7 + x2) = 0

Multiply (1 + 4x) * (-7 + x2)
3x(1(-7 + x2) + 4x * (-7 + x2)) = 0
3x((-7 * 1 + x2 * 1) + 4x * (-7 + x2)) = 0
3x((-7 + 1x2) + 4x * (-7 + x2)) = 0
3x(-7 + 1x2 + (-7 * 4x + x2 * 4x)) = 0
3x(-7 + 1x2 + (-28x + 4x3)) = 0

Reorder the terms:
3x(-7 + -28x + 1x2 + 4x3) = 0
3x(-7 + -28x + 1x2 + 4x3) = 0
(-7 * 3x + -28x * 3x + 1x2 * 3x + 4x3 * 3x) = 0
(-21x + -84x2 + 3x3 + 12x4) = 0

Solving
-21x + -84x2 + 3x3 + 12x4 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '3x'.
3x(-7 + -28x + x2 + 4x3) = 0

Ignore the factor 3.

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(-7 + -28x + x2 + 4x3)' equal to zero and attempt to solve:

Simplifying
-7 + -28x + x2 + 4x3 = 0

Solving
-7 + -28x + x2 + 4x3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
x = {0}

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